Question

An electron moving with a kinetic energy of 4.55 * 10-25. Calculate de-Broglie wavelength​

Answer 1

Answer:

Kinetic energy 21mv2=4.55×10−25J

m=9.1×10−31Kg

h=6.626×10−34Kgm2s−1

21×(9.1×10−31)v2=4.55×1025 (or)

v2=9.1×10−314.55×10−25×2=106

v=103msec−1

λ=mvh(9.1×10−33)×1036.626×10−34=7.5×10−7m

λ=7.25×10−7m