Question

an electron moving with a velocity of 10^5 ms^-1 enters into a uniform electric field and acquired uniform acceleration of 10^4 ms^-2 in the direction of its initial motion
(i) calculate the time in which the electron would acquire a velocity double of its initial velocity
(ii) how much distance the electron would cover in this time?
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Answer 1

Answer:

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Explanation:

Initial Velocity is the velocity at time interval t = 0 and it is represented by u. It is the velocity at which the motion starts. They are four initial velocity formulas: (1) If time, acceleration and final velocity are provided.

Answer 2

Answer:

5

Explanation:

The initial velocity of the electron is u =5X10⁴ m/s

Acceleration of the electron is a=10⁴ m/s²

From first equation of motion,

v=u+at

2u =u +at

t= u/a=(5×10⁴) // (10⁴)=5s