Question

An electron moving with a velocity of 100 m/ s enters into a uniform electric field and acquires a uniform acceleration of 10 m/s² in the direction of its initial motion. (11) How much distance the electron would cover in this time? (1) Calculate the time in which the electron would acquire a velocity double of its initial velocity​

Answer 1

Given data : An electron moving with a velocity of 100 m/s enters into a uniform electric field and acquires a uniform acceleration of 10 m/s² in the direction of its initial motion.

To find :

• Calculate the time in which the electron would acquire a velocity double of its initial velocity ?
• How much distance the electron would cover in this time ?

Solution :

• Initial velocity of the electron, u = 100 m/s
• Acceleration if the electron, a = 10 m/s²

Now, a/c to question;

velocity double of electron's initial velocity

➜ Final velocity, v = 2 {Initial velocity}

➜ Final velocity, v = 2 * 100

➜ Final velocity, v = 200 m/s

Hence, final velocity of the electron is 200 m/s

Now, we have to find out time taken, so we use kinematical equation;

➜ v = u + at

where, t is time

➜ 200 = 100 + 10t

➜ 200 - 100 = 10t

➜ 100 = 10t

➜ t = 100/10

➜ t = 10 sec

Now, to find out distance covered by electron in 10 sec. we use kinematical equation;

➜ s = ut + ½ * at²

where, s is displacement

➜ s = 100 * 10 + ½ * 10 * (10)²

➜ s = 1000 + 5 * 100

➜ s = 1000 + 500

➜ s = 1500 m

Answer : Hence, the time taken by the electron to attain double the initial velocity of the electron is 10 sec and distance covered by electron in 10 sec is 1500 m.

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