Question

An electron moving with a velocity of
5
×
10
3
m
/
s
enters into a uniform electric field and acquires a uniform acceleration of
10
3
m
/
s
2
in the direction of initial velocity.
i. Find out the time in which electron velocity will be doubled.?
ii. How much distance electron would cover in this time.?​

Answer 1

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Answer 2

Answer:Initial velocity of the electron is u =5×10  

4

 m/s

Acceleration of the electron is a=10  

4

 m/s  

2

 

From first equation of motion,  

v=u+at

2u=u+at

t=u/a=(5×10  

4

)/(10  

4

)=5s

(C) 5

Explanation: