an electron moving with a velocity of 5*10^4 m/s enters into a uniform electric field and acquires a uniform acceleration of 104m/s in the direction of its initial motion. a)calculate the time in which the electron would acquire a velocity double of its initial velocity. b)How much distance the electron would cover in this time.
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Given data:Initial velocity of the electron is, u = 5 × 10^4 m/sAcceleration of the electron is, a = 10^4 m/s2(i)Using, v = u + at=> 2u = u + at. [since v is double of Initial velocity (u)]=> t = u/a = (5 × 10^4)/( 10^4) = 5 s(ii)Distance travelled in this time is,S = ut + ½ at2=> S = (5 × 10^4) × 5 + ½ × 10^4 × 5^2=> S = 3,75,000 m
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Your answer will be 3 , 75, 000
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