Physics, asked by BhuvanKN15, 8 months ago

An electron moving with a velocity of 5 × 104 m/s enters into a uniform electric field and

acquires a uniform acceleration of 104 m/s²

in the direction of its initial motion.

(i) Calculate the time in which the electron would acquire a velocity double of its initial

velocity.

(ii) How much distance the electron would cover in this time?​

Answers

Answered by krishnadevi64
0

Answer:

(1)

Explanation:

calculator the time in which the electron would acquire a velocity double of its initial

Answered by dandamudisnivas
10

answer

Initial velocity of the electron is u =5×10

4

m/s

Acceleration of the electron is a=10

4

m/s

2

From first equation of motion,

v=u+at

2u=u+at

t=u/a=(5×10

4

)/(10

4

)=5s

(C) 5

Explanation:

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