Question

an electron moving with a velocity of 5 into 104 metre per second ² in the direction of its initial motion (i) calculate the time in which the electron would acquire a velocity double of its initial velocity (ii) how much distance the electron would cover in this time​

Answer 1

Answer:

Initial velocity of the electron is u =5×10  

4

 m/s

Acceleration of the electron is a=10  

4

 m/s  

2

 From first equation of motion,  

v=u+at

2u=u+at

t=u/a=(5×10  

4

)/(10  

4

)=5s

5 Ans.

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