Question

an electron moving with a velocity of 5 into 10power 4 metre per square enters into a uniform electric field and acquires a uniform acceleration of 10 power 4 metre per second square
a..find the time in which the electron would acquires a velocity double of its initial velocity
b..how much distance the electron will cover ​

Answer 1

Answer:

(i) 5s

(ii) 375000m

Explanation:

Given data:Initial velocity of the electron is,

u = 5 × 10^4 m/s

Acceleration of the electron is,

a = 10^4 m/s2

(i)

Using, v = u + at

=> 2u = u + at. [since v is double of Initial velocity (u)]

=> t = u/a = (5 × 10^4)/( 10^4) = 5 s

(ii)

Distance travelled in this time is,

S = ut + ½ at2

=> S = (5 × 10^4) × 5 + ½ × 10^4 × 5^2

=> S = 3,75,000 m

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