Question

An electron moving with a velocity of 5 x 104 m/s acquires a uniform acceleration of 104 m/s2 in the direction of motion. Calculate the time which electron would double its initial velocity. How much distance would it cover in this time?​

Answer 1

Answer:

Initial velocity of the electron is u =5×10

4

m/s

Acceleration of the electron is a=10

4

m/s

2

From first equation of motion,

v=u+at

2u=u+at

t=u/a=(5×10

4

)/(10

4

)=5s

(C) 5