An electron moving with a velocity of 5 x10^14 ms-1 enters into a uniform electric field and acquires a uniform acceleration of 10^4 m s-2 in the direction of its initial motion.
(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.
(ii) How much distance the electron would cover in this time?
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Answer:
Initial velocity of the electron is u =5×10
4
m/s
Acceleration of the electron is a=10
4
m/s
2
From first equation of motion,
v=u+at
2u=u+at
t=u/a=(5×10
4
)/(10
4
)=5s
(C) 5
Explanation:
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