Question

An electron moving with a velocity of 5x104 m/s enters into magnetic field and
acquires a uniform acc. of 104 m/s2 in the direction of its initial motion. Calculate the
time in which electron would acquire a velocity double of its initial velocity. How
much distance the electron would cover in this time?
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Answer 1

Answer:

time=10 seconds

distance= 10400meters or 10.4 km

Explanation:

An electron moving with a velocity of 5x104 m/s

velocity=5x104m/s=520m/s

and   acquires a uniform acc. of 104 m/s2

acceleration=104m/s2

Calculate the  time in which electron would acquire a velocity double of its initial velocity

(i.e find the time if the velocity was doubled)

velocity2=2(velocity1)

velocity2=2(520)=1040m/s

if acceleration=$\frac{velocity}{time}$

∴time=$\frac{velocity}{acceleration}$

time=$\frac{1040}{104}$

time=10 seconds

much distance the electron would cover in this time?

if velocity=$\frac{distance}{time}$

∴distance=velocity x time

distance= 10400meters or 10.4 km

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