An electron moving with a velocity of s 10-ms' enters into a uniform electric field
and acquires a uniform acceleration of 10'ms in the direction of its initial motion.
a) Calculate the time in which the electron would acquire a velocity double of its initial
velocity.
b)How much distance byhe electron would cover in this time?
Answers
Given data:Initial velocity of the electron is,
u = 5 × 10^4 m/s
Acceleration of the electron is,
a = 10^4 m/s2
(i)
Using, v = u + at
=> 2u = u + at. [since v is double of Initial velocity (u)]
=> t = u/a = (5 × 10^4)/( 10^4) = 5 s
(ii)
Distance travelled in this time is,
S = ut + ½ at2
=> S = (5 × 10^4) × 5 + ½ × 10^4 × 5^2
=> S = 3,75,000 m
hope my ans help you........ please mark it as brainliest.......
=================================××××=========
Answer:
Given data:Initial velocity of the electron is,
u = 5 × 10^4 m/s
Acceleration of the electron is,
a = 10^4 m/s2
(i)
Using, v = u + at
=> 2u = u + at. [since v is double of Initial velocity (u)]
=> t = u/a = (5 × 10^4)/( 10^4) = 5 s
(ii)
Distance travelled in this time is,
S = ut + ½ at2
=> S = (5 × 10^4) × 5 + ½ × 10^4 × 5^2
=> S = 3,75,000 m
hope my ans help you........ please mark it as brainliest.......
=================================××××=========