Question

An electron moving with kinetic energy 6 × 10⁻⁶ joules enters a field of magnetic induction 6 × 10⁻³ weber/m² at right angle to its motion. The radius of its path is(a) 3.42 cm(b) 4.23 cm(c) 5.17 cm(d) 7.7 cm

Answer 1

Option (b) is correct answer.

Answer 2

Answer:

The radius of its path is(a) 3.42 cm.

Explanation:

According to question , an electron moving with kinetic energy 6 × 10⁻⁶ joules enters a field of magnetic induction 6 × 10⁻³ weber/m² at right angle to its motion.

We need to find the radius of its path.

Kinetic Energy = $6 * 10^{-6} joules$

$or , \frac{1}{2} * mv^{2} = 6 * 10^{-6} \\\\or , v = \sqrt{\frac{12*10^{-6} }{m} }$

$r = \frac{mv}{qB}\\ \\or , r = \frac{m * \sqrt{\frac{12*10^{-6} }{m} } }{1.6*10^{-9} * 6 * 10^{-6} } \\\\or , r = 3.42 cm$

The radius of its path is(a) 3.42 cm.

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