Physics, asked by kanchankumari1, 1 year ago

an electron moving with the velocity of 5 into 10 to the power of 4 meter per second square in the direction of its initial motion and

Answers

Answered by ROSANNAKARYA03
1
(1) u (initial velocity) = 5 × 10⁴ m/s        v (final velocity) = 10⁵ m/s
              a (acceleration) = 10⁴ m/s²               t (time) = t (unknown)
              v = u + at
              100000 = 50000 + 10000×t
              100000 - 50000 = 10000×t
              50000 = 10000×t
              t = 50000 / 10000 = 5 s
         (2) s (distance) = (u + v) t / 2
                                = 5 (50000 + 100000) / 2
                                = 5×150000 / 2
                                = 750000 / 2
                                = 375000 m
                                = 3.75 × 10⁵ m    OR     375 km
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