An electron moving with velocity 2.2x10'6ms-1 isrevoving in a circular orbit of radius 0.53A.Calculate its angular momentum?
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Answer:
L = 106.34×10⁻³⁶ kg.m²/s
Explanation:
Given data:
Velocity of electron = 2.2×10⁶ ms⁻¹
Radius of circle = 0.53 A° (5.3×10⁻¹¹m)
Angular momentum = ?
Solution:
Formula:
L = mvr
L = Angular momentum
m = mass
v = Velocity
r = Radius
Mass of electron = 9.12 ×10⁻³¹ Kg
L = mvr
L = 9.12 ×10⁻³¹ Kg × 2.2×10⁶ ms⁻¹ ×5.3×10⁻¹¹m
L = 106.34×10⁻³⁶ kg.m²/s
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