Question

An electron of charge 1.6×10`19C situated in a uniform electric field of intensity 120000 N/C.
Calculate (1) the force on it (2)its acceleration (3)the time it takes to travel 20mm from rest.

Answer 1

Answer:

Put the formula to get the answer

Answer 2

1)Force on it is  1.92 *  $10^{-14}$ N.

2) Its acceleration is 2.11 *  $10^{16}$ m/s²

3) The time it takes to travel 20mm from rest is  13.74 *  $10^{-10}$ s.

Given:

An electron of charge(Q) 1.6× $10^{-19}$C and intensity(E) 120000 N/C

To Find:

1)Force

2) Acceleration

3) Time taken to travel 20mm from rest

Solution:

1) Formula E= F/Q

⇒ F = E*Q

= 120000 * 1.6 * $10^{-19}$

= 1.92 *  $10^{-14}$ N.

∴ Force on it is  1.92 *  $10^{-14}$ N.

2) F = m*a

⇒ a = F/m

⇒ a =  1.92 *  $10^{-14}$ / 9.1 *  $10^{-31}$

⇒ a = 2.11 *  $10^{16}$ m/s²

∴ Its acceleration is 2.11 *  $10^{16}$ m/s²

3)  S= ut + at²/2

At rest u = 0

⇒ S= at²/2

⇒ t² = 2S/a

⇒ t² = 2* 20 *   $10^{-3}$ /  2.11 *  $10^{16}$

⇒ t² = 189.5 * $10^{-20}$

⇒ t = √189.5 * $10^{-20}$

⇒ t = 13.74 *  $10^{-10}$ s.

∴ The time it takes to travel 20mm from rest is  13.74 *  $10^{-10}$ s.

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