Question

An electron of charge -e circulate a helium nucleus of charge 2e in a helium atom.
which particle exerts the larger force on the other.​

Answer 1

Answer:

An electron of charge -e circulate a helium nucleus of charge 2e in a helium atom.

which particle exerts the larger force on the other.

Explanation:

An electron of charge -e circulate a helium nucleus of charge 2e in a helium atom.

which particle exerts the larger force on the other.An electron of charge -e circulate a helium nucleus of charge 2e in a helium atom.

which particle exerts the larger force on the other.An electron of charge -e circulate a helium nucleus of charge 2e in a helium atom.

which particle exerts the larger force on the other..⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽.⚽

⚽

⚽

.

✨

✨✨✨✨

✨✨✨ ✨

✨

⛳

⛳.

✨

✨✨✨✨

✨✨✨ ✨

✨

⛳

⛳.

✨

✨✨✨✨

✨✨✨ ✨

✨

⛳

⛳.

✨

✨✨✨✨

✨✨✨ ✨

✨

⛳

⛳.

✨

✨✨✨✨

✨✨✨ ✨

✨

⛳

⛳.

✨

✨✨✨✨

✨✨✨ ✨

✨

⛳

⛳.

✨

✨✨✨✨

✨✨✨ ✨

✨

⛳ . ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳. ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳. ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳. ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳. ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳. ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳. ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳. ⛳❤❤⛳❤❤⛳

❤❤ ⚪⚪⚪ ❤❤

❤⚪⚪⚪⚪⚪❤

⛳❤⚪⚪⚪❤⛳

⛳⛳❤⚪❤⛳⛳

⛳⛳⛳❤⛳⛳⛳.⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽.⚽

⚽

⚽

⚽

⛳

⚽

Answer 2

Answer:

An electron of charge -e circulates a helium nucleus of charge 2e in a helium atom. The force on electron due to helium core is equal to the force on helium core due to the electron but in opposite direction.

Explanation:

• When two charges $q_{1} ,q_{2}$ are separated by a distance $r$, their mutual interaction is called electrostatic force which is given by the formula

                              $F=\frac{q_1q_2}{4\pi \varepsilon _0r^2}$

         where $\frac{1}{4\pi \varepsilon _0}=9*10^{9}$

from the question, an electron circulates helium nucleus

the charge of an electron $e=-1.6*10^{-19}C$

the charge of the helium core $+2e=+2*1.6*10^{-19}$

let the distance from electron to helium core be $r$

the force on the electron due to the helium core is $F_{1} =\frac{9*10^{9}*2e^{2} }{r^{2} }$

the distance from the helium core to the electron is $r$  again

the force on the helium core due to the electron is $F_{2} =\frac{9*10^{9}*2e^{2} }{r^{2} }$

it is clear that $F_{1} =F_{2}$ that is both the forces are the same in magnitude