Question

An electron of mass 9×10^-31 kg is revolve in stable orbit of radius 5.7×10^-34 m. If electrostatic force of attraction electron and proton is 8×10^-8 N. Find the velocity of electron.​

Answer 1

Answer:

From Coulomb's inverse square law: F=4πε01r2q1q2

The magnitude of charge on electron and proton is the same =1.6×10−19C

Therefore, electrostatic force is given by

F=(0.05×10−9)29×109×1.6×10−19×1.6×10−19

=(5×10−11)29×1.6×1.6×10−29

=25×10−229×1.6×1.6×10−29

=0.9216×10−29×10+22

=0.9216×10−7N

=9.216×10−8N