Question

An electron of mass 9×10^-31kg is moving with a linear velocity of 6×10^7ms-1.calculate the linear momentum of electron

Answer 1

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$m = 9 \times {10}^{ - 31} kg \\ v \: = 6 \times {10}^{7} mps \\ \\ p \: = mv \\ = 9 \times {10}^{ - 31} \times 6 \times {10}^{7} \\ 54 \times {10}^{ - 31 + 7} \\ 54 \times {10}^{ - 24}$