Question

An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is :

Answer 1

https://www.youtube.com/channel/UCIMjS0ZIyJ503LaflbgUKfw?view_as=subscriber

Answer 2

Answer:

1/c (E/2m)¹∕₂.

Explanation:

Mass of electron = m (Given)

Energy between electron and photon = E (Given)

According to the de-Broglie wavelengths

λₑ = h / √2mE,

For the photon of energy -

λp = hc / E,

E = hc / λp

λₑ / λp = (h / √2mE) × (E / hc)

= 1/c √(E / 2m)

= 1/c (E/2m)¹∕₂

Thus,  ratio of de-Broglie wavelengths associated with them is 1/c (E/2m)¹∕₂.