Question

An electron of mass m and a proton have same enery e the ratio of de broglkie

Answer 1

Answer:

1/c (E/2m)¹∕₂

Explanation:

λₑ = h / √2mE,

λp = hc / E,

E = hc / λp

λₑ / λp = (h / √2mE) (E / hc)

= 1/c √(E / 2m)

=1/c (E/2m)¹∕₂