An electron of mass m and a proton have same enery e the ratio of de broglkie
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Answer:
1/c (E/2m)¹∕₂
Explanation:
λₑ = h / √2mE,
λp = hc / E,
E = hc / λp
λₑ / λp = (h / √2mE) (E / hc)
= 1/c √(E / 2m)
=1/c (E/2m)¹∕₂
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