Question

An electron of mass m and charge e is accelerated
from rest through a potential difference of V volt
in vacuum. Its final speed will be
(a) ???????? (b) ????????
2???? ????
(c)⎷ 2???????? (d) ⎷????????
???? 2????

Answer 1

QUESTION:

An electron of mass m and charge e is accelerated from rest through a potential difference of V volt in vacuum. Its final speed will be

• (a) eV/2m

• (b) eV/m

• (c)⎷(2eV/m)

• (d) ⎷(eV/m)

ANSWER:

• The final speed of the electron = √(2eV/m).

GIVEN:

• An electron of mass m and charge e is accelerated from rest in vacuum.

• Potential difference is V volt.

TO FIND:

• The final speed of the electron.

EXPLANATION:

$\boxed{ \bold{ \large{ \blue{K.E = eV}}}}$

$\tt \leadsto\dfrac{1}{2}mv^2 = eV$

$\tt \leadsto\dfrac{1}{2}v^2 =\dfrac{eV}{n}$

$\tt \leadsto v^2 = \dfrac{2eV}{m}$

$\tt \leadsto v= \sqrt{ \dfrac{2eV}{m}}$

Hence the final speed of the electron = √(2eV/m).

Answer 2

$\huge\color{purple}{\underline{\underline{Answer\::}}}$

√(2ev/m)

$\huge\color{yellow}{\underline{\underline{explanation\::}}}$

Refers to the attachment...