Physics, asked by pratyksh75, 1 year ago

An electron of mass M initially at rest, moves through a certain distance in a uniform electric field in timet,
A proton of mass M also initially at rest, takes time t, to move through an equal distance in this riform
electric field. Neglecting the effect of gravity, the ratio t/t, is nearly equal to​

Answers

Answered by sonuvuce
30

Answer:

\boldsymbol{\frac{t_2}{t_1} =\sqrt{\frac{M_p}{M_e}}}

Explanation:

If the acceleration is a then the distance s travelled in time t is given by

s=\frac{1}{2}at^2

Therefore for electron

s=\frac{1}{2}a_et_1^2

And for Electron

s=\frac{1}{2}a_pt_2^2

Thus,

\frac{t_2}{t_1} =\sqrt{\frac{a_e}{a_p}}  .......... (1)

Force on electron in an electric field E

F_e=eE

Thus the acceleration of the electron if its mass is M_e

a_e=\frac{F_e}{M_e} =\frac{eE}{M_e}

Similarly the acceleration of the proton

a_p=\frac{F_e}{M_p} =\frac{eE}{M_p}

Therefore,

\frac{a_e}{a_p}=\frac{M_p}{M_e}

Therefore, from (1)

\frac{t_2}{t_1} =\sqrt{\frac{M_p}{M_e}}

Answered by Anonymous
9

Answer:

√ ae/ ap = √ mp/me

Explanation:

Mass of the electron = M (Given)

Mass of the proton = M (Given)

Time = t (Given)

Electrostatic force, FE = eE (for both electron and proton)  

But acceleration of electron, ae =FE/me whereas -  

acceleration of proton, ap = FE/mp

S = 1/2at²1 = 1/2apt²2  

Therefore,

t2/t1 = √ ae/ ap

t2/ t1 = √ ae/ ap = √ mp/me

Thus, the ratio is nearly equal to - √ ae/ ap = √ mp/me

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