An electron of velocity 'V' is found to have a certain value of de - broglie wave length. The
velocity to be possessed by the neutron to have the same de-broglie wavelength is
1) v
2) v/1840 3) 1840 v
4) 1840/v
Answers
Answered by
2
Answer:
2) v/1840
Explanation:
De-Broglie wavelength is given by:
λ = h/mv
Let 1 represents electron and 2 represents neutron.
λ = h/m1v1 = h/m2v2
m1v1 = m2v2
v2 = m1v1/m2
v2 = v(m1/m2)
v2 = v(m1/1840m1)
v2 = v/1840
Answered by
2
v2 = Answer:
2) v/1840
Explanation:
De-Broglie wavelength is given by:
λ = h/mv
Let 1 represents electron and 2 represents neutron.
λ = h/m1v1 = h/m2v2
m1v1 = m2v2
v2 = m1v1/m2
v2 = v(m1/m2)
v2 = v(m1/1840m1)
v2 = v/1840
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