Question

An electron placed in an electric field, experiences a force F of 1 N. What are the magnitude and direction of electric field E at the point where the electron is located (e=1.6*10^-19C)

Answer 1

Given :

Force on the electron = 1 N

Charge of electron , e = 1.6 * 10 ^ (-19) C

To find :

The magnitude and direction of electric field E.

Solution :

Force = charge * electric field

=> Force = q * E

=> Force = e * E    {Here , q = e}

=> 1 = 1.6 * 10 ^ (-19) * E

=> E = 1 / [ 1.6 * 10 ^ (-19) ]

=> E = 6.25 *  10 ^ (18) N/C

Direction of field is opposite to the direction of the force .

The magnitude of electric field E is 6.25 *  10 ^ (18) N/C and the direction of electric field E is opposite to the direction of the force .