Question

An electron revolves in an orbit of nucleus of hydrogen atom of radius 0.5A with velocity 3*10^6 m/s what is M

Answer 1

Answer:

Given, r=0.2

A

o

=2×10

−11

m,v=10

5

m/s

e=1.6×10

−19

C

B=?

∵I=

t

q

=

T

e

=e(

2πr

v

)

Also, B=

2r

μ

0

I

=

2r

μ

0

2

2πr

v

=

4π

μ

0

×

r

2

ev

=10

−7

×

(2×10

−11

)

2

1.6×10

−19

×10

5

=

4×10

−22

1.6×10

−21

=4T.

Explanation:

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