Physics, asked by divyeshkelaiya, 5 hours ago

An electron revolves with frequency 6.6 x1015 r.p.s.
around nucleus in circular orbit of radius
0.53 Å of hydrogen atom, then magnetic field
produced at centre of orbit is :-
(1) 0.125 T (2) 1.25 T (3) 12.5 T (4) 125 T​

Answers

Answered by manoranjanphy1
9

Explanation:

current constitute due to revolution by electron around the nucleus is

I = q/t = e/ t = e x frequency

= 1.6 x 10 ^-19 x 6.6 x 10¹⁵

= 1.6 x 6.6 x 10^-4

B = 4π x 10^-7 x I / 2r

=( 4π x 10^-7 x 1.6 x 6.6 x 10^-4)/ 2 x0.53 x 10^-10

= 125 x 10³ x 10^-4

= 125 /10

= 12.5T

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