An electron revolves with frequency 6.6 x1015 r.p.s.
around nucleus in circular orbit of radius
0.53 Å of hydrogen atom, then magnetic field
produced at centre of orbit is :-
(1) 0.125 T (2) 1.25 T (3) 12.5 T (4) 125 T
Answers
Answered by
9
Explanation:
current constitute due to revolution by electron around the nucleus is
I = q/t = e/ t = e x frequency
= 1.6 x 10 ^-19 x 6.6 x 10¹⁵
= 1.6 x 6.6 x 10^-4
B = 4π x 10^-7 x I / 2r
=( 4π x 10^-7 x 1.6 x 6.6 x 10^-4)/ 2 x0.53 x 10^-10
= 125 x 10³ x 10^-4
= 125 /10
= 12.5T
Similar questions