Question

An electron starting from rest has a velocity that increases linearly with time i.e v=kt where k=2ms−2. the distance covered in the first 3 second is

Answer 1

Answer : 9 m
dS=ktdt
S=12kt2
=12×2×3×3m=9m
=9m

Answer 2

Given that,

An electron starting from rest has a velocity that increases linearly with time i.e v=kt where k=2ms⁻²

To find,

The distance covered in the first 3 seconds.

Solution,

Velocity of an electron is given by :

v=kt

Since, $v=\dfrac{dx}{dt}$

$\dfrac{dx}{dt}=kt\\\\x=\int\limits \, (ktdt)\\\\x=\dfrac{kt^2}{2}$

k = 2 m/s²

So, at t = 3 s

$x=\dfrac{2\times 3^2}{2}\\\\x=9\ m$

So, the distance covered in first 3 second is 9 m.

Learn more,

Kinematics

https://brainly.in/question/13569372