An electron travelling with a speed of 5 x 103m/s passes through an electric field with an acceleration of 1012 m/s2. How long will it take for the electron to double its speed?
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Dear Student,Please find below the solution to the asked query:
Final velocity:
v=u+at
t=v−u/a
=2u−u/a
=u/a
=5×10^3/1012
=5×10−9 sec.
Final velocity:
v=u+at
t=v−u/a
=2u−u/a
=u/a
=5×10^3/1012
=5×10−9 sec.
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