Question

an electron travelling with a speed of
$u = 5 \times {10}^{3} \:m {s}^{ - 1}$
passes through an electric field with an acceleration of
$a = { 10}^{12} m {s}^{ - 2}$
1. How long will it take for the electron to double its speed ?
2. What will be the distance covered by the electron in this time ?
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Answer 1

Answer:

$\underline{\purple{\ddot{\Mathsdude}}}$

Given:-

• Speed = v= 5×10^3m/s

• Acceleration =a= 10^12m/s^2.

To find :-

1. How long it will take for the electron to double its speed.?
2. Distance covered by the electron in this time ?

Explanation :-

i)

• Consider Initial velocity =u
• Final velocity =2u

By using equation of motion Formula .

• v=u+at
• t= v-u/a.
• t=2u-u/a.
• t= u/a
• t=5×10^3/10^12
• t=5×10^-9sec.

ii) The distance covered by the electron in this time will be

• D= v×t
• D= 5×10^3×5×10^-9
• D = 25×10^-6.

♧♧Hope it helps u mate.

♧♧Thank you.