Question

An electron travels with a velocity of v m/s for a photon to have the same de Broglie wavelength the velocity will be?(approximately)

Answer 1

Answer:

       $v_{p}$ = v / 1840

Explanation:

λ = h / mv

where    λ - wavelength

              h - Planck's constant

              m - mass

               v - velocity

λ = h / $m_{e} v_{e}$ ----{ii}

$m_{e} v_{e}$ - mass of electron × velocity of electron

λ = h / $m_{p} v_{p}$ ----{i}

$m_{p} v_{p}$ - mass of proton × velocity of proton

de Broglie wavelength is equal

{i} = {ii}

h / $m_{e} v_{e}$ = h / $m_{p} v_{p}$

1 / $m_{e} v_{e}$ = 1 / $m_{p} v_{p}$

$m_{e} v_{e}$ = $m_{p} v_{p}$

$m_{p } = 1840$ × $m_{e}$

$m_{e} v_{e}$ = 1840 × $m_{e} v_{p}$

v = 1840 × $v_{p}$

$v_{p}$ =$\frac{v}{1840}$