An electron with an initial speed of 12m/s Eastward experiences a constant acceleration of 4m/s^(2) west for 4 seconds.During this time the object travels a distance of:
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Answered by
0
Answer:
s=ut+1/2at^2
=12(4)+1/2(-4)(4)^2
=48-32
=16
rahulvimal133:
Actually the answer is wrong.
48 + 32=80 ......??
i have - ve sign since velocity and acceleration are in opposite direction
The answer is 20m
I just know the answer but regret to get it
Answered by
3
Answer:
Answer is 20m/s²
Explanation:
Step by step explanation is in the picture
Hope u understand :)
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