Physics, asked by krushna1135, 1 year ago

An electron with change e enters a uniform magnetic field B with a velocity v .The velocity is perpendicular to the magnetic field . The force on the change a is given by

Answers

Answered by anamikapradeep7
1

hey mate...

here is your answer...

The dimensions of Flux Density, B is M/T2I.

Explanation:

If charge moving at right angles to the field

F = -Bev for an electron ( e = charge on an electron)

Remember that the direction of conventional current is opposite to that of the electron.

Here, F is force measured in newtons (N)

B is flux density (the strength of a magnetic field I.e No. of magnetic lines of force from magnet per unit area) measured in teslas (T, named after Nikola Tesla)

So, The dimensions of Flux Density, B is MT^-2I^-1.

hope it helps...

Answered by Anonymous
5

We know that The force on electron in magnetic field = Bevsin@

since @ =90°

so

Force = BeV sin90°

Force = BeV newton .

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