an electron with charge -e and mass m travels at a speed v in a plane perpendicular to a magnetic field of magnitude B.the electron follows a circular path of radius R.In a time t the electron travels halfway around the circle.what is the amount of work done by the magnetic field?
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The magnetic force on the electrom provides the centripetal force, so, we have,
bqv = mv²/R ⇒R = mv/bq
So, if velocity is doubled and magnetic field intensity is halved, then the radius will become 4 times.
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The amount of work done by magnetic field is Zero
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