Question

An electron with charge e enters a uniform.
magnetic field B with a velocity v. The
velocity is perpendicular to the magnetic
field. The force on the charge e is given
by
F =Bev Obtain the dimensions of B.
[Ans: [L'MºT?I']]​

Answer 1

Answer:

The dimensions of Flux Density, B is M/T2I.

Explanation:

If charge moving at right angles to the field

F = -Bev for an electron ( e = charge on an electron)

Remember that the direction of conventional current is opposite to that of the electron.

Here, F is force measured in newtons (N)

B is flux density (the strength of a magnetic field I.e No. of magnetic lines of force from magnet per unit area) measured in teslas (T, named after Nikola Tesla)

So, The dimensions of Flux Density, B is MT^-2I^-1.

Answer 2

Answer:

Explanation:

The dimensions of B is equal to

[M^1L^0T^-2I^-1