Question

An electron with charge e enters a uniform
magnetic field B with a velocity v. The
velocity is perpendicular to the magnetic
field. The force on the charge e is given
by
|F|= Bev Obtain the dimensions of B.​

Answer 1

Answer:

The dimension of B is Ns÷qm

Explanation:

The dimension of force is given by Newton N

The dimension of charge e is coulomb q

The dimension of velocity is m/s

N = B ×q × m÷s

The dimension of B is Ns÷qm  Where m is meter, q is coloumb, s is seconds and N is newton

Answer 2

Answer:

Your answer is in the attached files.....