Physics, asked by paarti6406, 1 year ago

An electron with mass 9.11 1031 kg has a velocity of 4.30 105 m/s in the innermost orbit of a hydrogen atom. What is the de broglie wavelength of the electron?

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Answered by girlinblue1021
8

Answer:

An electron with a mass of 9.11x10-31 kg has a velocity of 4.3 x 106 m/s in the innermost orbit of a hydrogen atom. What is the de Broglie wavelength of the electron?

The de Broglie wavelength is give by h/p or h/mv, whereh is the Planck's constant h=6.6262x10^-34 (J s), p is the momentum=mv or mass x velocity. We know 1 J=1 kg m^2/s^2

So, the wavelength is h/mv =(h=6.6262x10^-34 J s)/(9.11x10^-31 kg x 4.3x10^6 m/s) =1.6915x10^-10 (m) or 1.6915 (A, angstrom)

Answered by playboy12
1

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