Question

An electronic bulb drow 2.5 A current at 10v find the resistance of the filament of bulb

Answer 1

$\checkmark$ Given:

An electronic bulb draws 2.5 A current at 10 V

$\checkmark$ To Find:

The resistance of the filament of bulb

$\checkmark$ Solution:

We know that,

$\dagger$ Ohm's Law:

$\red{\bigstar \ \boxed{\rm V=IR}}$

Here,

• V = voltage
• I = current
• R = resistance

$\star$ Units:

• V = Voltage (V)
• I = Ampere (A)
• R = Ohm (Ω)

According to the question,

We are asked to find the resistance of the filament of bulb

So, we must find "R"

Therefore,

$\orange{\bigstar \ \boxed{\rm R=\dfrac{V}{I}}}$

Given that,

An electronic bulb draws 2.5 A current at 10 V

Hence,

• V = 10 V
• I = 2.5 A

By substituting the values,

We get,

$\blue{\implies \rm R=\dfrac{10}{2.5} \ \Omega}$

On further simplification,

We get,

$\green{\implies \rm R=4 \ \Omega}$

Hence,

$\pink{\bigstar \ \boxed{\rm Resistance \ (R)=4 \ \Omega}}$

Therefore,

The resistance of the filament of bulb = 4 Ω

Answer 2

Given ,

Current (I) = 2.5 Amp

Potential difference (v) = 10 v

We know that , the relationship between current and potential difference is given by

$\boxed{ \tt{V = IR}}$

Where , R = Resistance

Thus ,

$\sf \mapsto 10 = 2.5 \times R</p><p></p><p>$

$\sf \mapsto R = \frac{10}{2.5}$

$\sf \mapsto R = 4 \: \: ohm$

Therefore , the resistance of the filament of bulb is 4 ohm