Math, asked by Ayas9943, 9 months ago

An electronic clock makes a beep after every 58 secs. Another makes after every 60 secs. They beeped together at 11.11 a.m. The time when they would beep together next is
(a) 11.28 a.m. (b) 11.39 a.m. (c) 11.52 a.m. (d) 11.42 a.m

Answers

Answered by Emz101
0

Answer:

11:40am

Step-by-step explanation:

(hour:minutes:seconds)

Beep A: 11:11:00, 11:11:58, 11:12:56, 11:13:54, 11:14:52, 11:15:50 and so on until 11:40am

Beep B: 11:11, 11:12, 11:13, 11:14, 11:15 And so on until 11:40am

Hope this helps

Answered by SrijanAdhikari23
0

Disclaimer: None of the options is correct in the given question.

The two clocks will beep again together at 11.40 AM .

Given:

The first clock beeps after 58 seconds

The second clock beeps after 60 seconds

They beeped together at 11.11 AM

To find:

The time when they will beep again together.

Solution:

The two clocks beeped at 11.11 AM. The first clock and the second clock beep at different intervals of time.

So we have to find the LCM of the two intervals and we will get the exact moment when they would beep again.

LCM of 58 and 60 = 2\times 30\times 29 = 1740

So the clocks will again beep after 1740 seconds.

Now we have to convert the seconds to minutes.

Therefore:

1740\div 60 = 29 minutes

So the time when the clocks will beep again :

11.11+0.29=11.40 \text{ AM}

Therefore both the clocks will beep again at 11.40 AM, as calculated using Lowest Common multiple (LCM).

To learn more about Lowest Common multiple (LCM)  visit:

https://brainly.in/question/2029238

https://brainly.in/question/36661060

#SPJ3

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