Question

An electronic gadget produce light after 15 minutes whereas electronic rod gives light after 20 minutes they produce light together at 12:00 a.m. at what time will they produce light together

Answer 1

In the above Question , the following information is given -

An electronic gadget produce light after 15 minutes .

An electronic rod gives light after 20 minutes.

They produce light together at 12:00 a.m.

To find -

The next time when they will produce light again .

Concept Used -

LCM and HCF

Solution -

Here , we have to find the next time when they will produce light again .

So , this means that we have to find the LCM of the different timings .

So.,

Here -

An electronic gadget produce light after 15 minutes .

An electronic rod gives light after 20 minutes.

LCM of 15 and 20

5 |__15, ___20__

1 |___3____4__

So .

LCM

=> 5 × 3 × 4

=> 60 minutes .

We know that -

1 hour = 60 minutes .

So.

The two lights will blink again after an hour .

They first blinked at 12 : 00 am .

So, they will blink again at 1 : 00 am ... Answer

_______________

Additional information -

LCM × HCF = Product of Numbers

Answer 2

$\huge\sf\pink{Answer}$

☞ They will ring back together at 1 pm

$\rule{110}1$

$\huge\sf\blue{Given}$

➳ An electronic gadget produces light after 15 minutes

➳ An electronic rid gives light after 20 minutes

➳ They produce light together at 12:00 am

$\rule{110}1$

$\huge\sf\gray{To \:Find}$

✭ The time when they produce light together again?

$\rule{110}1$

$\huge\sf\purple{Steps}$

❍ So your answer can just be found by finding the LCM of (15,20)

So the LCM of the two numbers is,

$\sf 5| \underline{15,20} \\ \sf 1| \underline{3,4 \: \: \: \: \: }$

So their LCM is equal to 5×3×4

So the LCM of (15,20) = 60

☆ We know that 60 minutes = $\sf\red{1 \:hour}$

So they will ring back together at $\sf\large\orange{1\:pm}$

$\rule{170}3$