an electronic iron consumed energy at the rate of 880 w when heating is at the maximum rate and 440 w when heating at the minimum rate the applied voptage is 220 v calculate the current and resistance in each case
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Hey.
Power = V × I
For maximum case :
P = 880 W = 220× Im
so, Imax = 880/220 = 4 A
Also R = V/I
so, Rmax = 220/4 = 55 ohm
Similarly
For Minimum case:
P = 440 W = 220×Imin
so, Imin = 440/220 = 2 A
and R min = V/I = 220/2 = 110 ohms
Thanks.
Power = V × I
For maximum case :
P = 880 W = 220× Im
so, Imax = 880/220 = 4 A
Also R = V/I
so, Rmax = 220/4 = 55 ohm
Similarly
For Minimum case:
P = 440 W = 220×Imin
so, Imin = 440/220 = 2 A
and R min = V/I = 220/2 = 110 ohms
Thanks.
Furyous:
thanks bro
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