Question

An electronic iron consumed energy at the rate of 880W when heating is at the maximum rate and 440W when the heating is at the minimum rate. the applied voltage is 220V. calculate the current and resistance in each case. ​

Answer 1

Answer:

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Answer 2

Answer:

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ANSWER = when heating is maximum the current is 4 amperes and when the heating is minimum the current is 2 amperes.

Explanation:

Given= power1 = 880w, power 2 = 440w and voltage =220v

we know that,

$power = voltage \times current$

Current drawn maximum I =power/voltage

$= \frac{880}{220}$

$= 4 ampere$

current drawn minimum I=power/voltage

$= \frac{440}{220}$

$= 2 ampere$

Formula of resistance =》

R= V²/ P

In first case》》

R= (220)²/880

R =48400/880

R = 55 ohm

In second case 》》

R=(220)²/440

R=48400/440

R= 110

So, the resistance in 880w is 55 ohm , and resistance in 220w is 110 ohm.