Question

An element A belongs to 2rd period and 17th group of the periodic table. i) Write electronic configuration of element A ii) State whether element A is metal or nonmetal. iii) Write the formula of a compound formed if A reacts with element B which has the smallest atomic size in group 2.

Answer 1

Answer:

(i) 2,8,7

(ii) Non metal

(iii) BA2 (beryllium chloride, becl2)

Explanation:

(i). Refer to the periodic table

(ii) Non metals gain electrons and have negative valencies. clearly, chlorine is a non metal.

(iii) element B is berrylium. they form a covelant compound.

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Answer 2

Explanation:

Given -

• Element A belongs to 2nd period and 17th group of the periodic table.

To Find -

1. Write electronic configuration of element.
2. State whether Element A is metal or non-metal.
3. Write the formula of a compound formed if A reacts with element B which has the smallest atomic size in group 2.

Solution -

Element A belong to 17th group. It is cleared that, Element A is Halogen.

And

Element A belong to 2nd period. It is cleared that, Element A is Flourine (F).

1)

Electronic configuration of F -

$\mathsf{ {1s}^{2} {2s}^{2} {2p}^{5} }$

2)

Element A is non-metal.

3)

We know that, Beryllium has the smallest size in Group 2.

Then, Beryllium reacts with Flourine to form BeF2 (BA2).