Biology, asked by goodygal1010, 1 year ago

an element A burns with golden flame in air. it reacts with another element B, atomic number 17 to give a product C. An aqueous solutions of product C on electrolysis gives a compound D and liberates hydrogen. Identify A,B,C,D and write down the equation for the reaction involved

Answers

Answered by AdeleDavis
3
A is sodium
B is chlorine
C is Sodium chloride

D and C I don't know

123lokendra: r u crazy or just giving incomplete answers
AdeleDavis: I am not crazy....I was helping you. D and C I don't know so I didn't write. What do you mean by crazy......I was just answering your question. I am sure that the ones I gave are correct but I am not getting the others.
Answered by itemderby
14

Explanation:

Element which gives golden flame on heating is sodium. Therefore, A is sodium.

Element whose atomic number is 17, is chlorine. Therefore, B is chlorine.

When element A and B reacts with each other then the reaction will be as follows.

            Na + Cl \rightarrow NaCl

Hence, from the reaction we can see that compound C is NaCl (sodium chloride).

Now, chemical equation for electrolysis of aqueous solution of compound C is as follows.

    2NaCl + 2H_{2}O \rightarrow 2NaOH + Cl_{2} + H_{2}

Thus, compound D is NaOH (sodium hydroxide).

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