An element A burns with golden flame in air . It reacts with another element B, atomic number 17 to give a product C. Indentify A, B, C and D. Also write down the equation for the reactions involved .
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An element A burns with golden flame in air. It reacts with another element B, atomic number 17 to give a product C. ... Answer: A is sodium (burns with golden flame), B is chlorine (atomic number 7), C is sodium chloride and D is sodium hydroxide. When sodium reacts with chlorine, it gives sodium chloride
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Since the element 'A' catches fire in water and burns with golden yellow flame, it is sodium (Na). The element 'B' with atomic number 17 is chlorine (Cl). Both these combine to form sodium chloride (NaCl) which is designated as 'C'.
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