An element A decays into an element C by a two step process
A ➝ B + 2He⁴ and B ➝ C + 2e- . Then,
(a) A and C are isotopes
(b) A and C are isobars
(c) B and C are isotopes
(d) A and B are isobars
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Answer:
Isobars are atoms with same mass number but different atomic number.
Let atomic number of A be Z
Let mass number of A be X
A⟶
2
He
4
+B
Therefore, Atomic number of B will be Z−2
Mass number of B will be Z−4
B⟶2(
−1
e
0
)+C
Therefore, Atomic number of C will be Z
Mass number of C will be Z−4
It can be seen that B and C have same mass number but different atomic number. Hence, B and C are isobars.
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