An element A exist both as AlCl2 and AlCl4. When 10 g of AlCl2 is reacted with excess chlorine 24.8 g of AlCl4 is produced. what is the identity of the unknown element A ? is it V , B , or Au ?
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hey mate your answer
First, you need to find the number of moles of aluminum chloride.
moles = mass/rmm
10
g
26.98
+
3
(
35.453
)
= 0.075 moles
Since the equation states that for every 3 molecules of aluminum chloride, you produce 2 molecules of chlorine, by cross-multiplying the amount of moles, you obtain 0.1125 moles of chlorine produced.
Now, just convert moles to grams by rearranging the formula earlier, and you should obtain 7.98 grams (rounded to 2 decimal places)
I hope it's helped you please make me a brainlist
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