Chemistry, asked by SleetyMallard1104, 1 year ago

An element a exist in two isotopic forms a^15 and a ^16 . if average atomic mass of a was found to be 15.24 then %relative abundance of a^15 is

Answers

Answered by Srivathsa11
5
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Answered by RomeliaThurston
4

Answer: Percentage abundance of A^{15} isotope is 76%

Explanation: We are given average atomic mass of element A is 15.24 amu.

Formula of average atomic mass:

\text{Average atomic mass of an element}=\sum_{i=1}^n(\text{Atomic mass})_i(\text{Fractional abundance})_i     ....(1)

We take fractional abundance of A^{15} isotope = x

Mass of A^{15} isotope = 15 amu

Fractional isotope of A^{16} isotope = (1 - x)

Mass of A^{16} isotope = 16 amu

Putting all the values in equation (1), we get

15.24=(15)(x)+(16)(1-x)

x = 0.76

As we need to find the percentage abundance, we multiply the fractional abundance by 100.

\% \text{ abundance}=0.76\times 100

Percentage abundance of A^{15} = 76%

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