an element atomic mass 100 g/mol having bcc structure has unit cell edge 400 pm. the density of the elements is
Answers
Answered by
0
Answer:
Given, M = 100 g/mol, a = 400pm
n=8×1/8 +1=2
As we know,
Density= n×M /a³ ×Nₐ
2×100/(400×10⁻¹⁰)³ ×6.02× 10²³
=5.188 g cm ⁻³
Similar questions