Question

an element atomic mass 60 having fcc has a density of 6.23gper cm cube .what is edge length of unit cell?​

Answer 1

Answer:

400 pm

Explanation:

d = Z × M/ a^3 × Avogadro no

Z in Fcc = 1/2 × 6 + 1 = 4

a^ 3 = 4 × 60/ 6.23 × 6.022 × 10^ 23

a = 400 × 10 ^ -10 m

Answer 2

Answer:

400 pm

Explanation:

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